Question

Acidified water was electrolysed using an inert electrode and volume of gases liberated at stp was 168 ml. The amount of electricity passed through water was

Answer 1

Hello buddy,

● Answer- 965 C.

● Explaination-
Electrolytis of acidified water occurs as follows-
2H20 ---> 2H2 + O2
Initial m 2x x
Equilb. m-x 2x x

Hence, 2x+x = 3x liberated
3x = 168 ml = 0.168 l
x = 0.056 l

V(H2) = 0.112 l
V(O2) = 0.056 l

We know electricity passed through 11.2 l H2 is 1 F.
For 0.112 l H2,
I = 1F/100 = 0.01 F
I = 0.01 × 96500
I = 965 C

Amount of electricity paased will be 965 C.

Hope this is useful...