Question

ACIIGE and
11. In the given figure : ABI/FD, ACH
BD = CE; prove that :
(i) BG = DF
(ii) CF = EG.
B​

Answer 1

Step-by-step explanation:

BE= BD+DE=CE+DE=CD.

BE=CD

angle FDC=angle GBE (GB||FD)

angle FCD= angle GEB(GE||FC)

hence, triangleGBE congruent to triangle FDC.

thus,BG=DF and CF= EG