Acircular park of 28m diameter has been constructed.A3.5m circular track outside has been developed along the park.using algebra formulae,finf the area of track around the park.
Answers
Answered by
0
Given d = 28m, r = d/2 = 14, w = 3.5m
We know that Area of the track = pi(R^2 - r^2) ------------- (1)
R = r + w
= 14 + 3.5
= 17.5m.
Substitute in (1), we get
A = pi(17.5^2 - 14^2)
= pi(17.5 + 14)(17.5-14)
= pi(31.5)(3.5)
= 22 * 31.5 * 3.5/7
= 346.5 sq.m.
We know that Area of the track = pi(R^2 - r^2) ------------- (1)
R = r + w
= 14 + 3.5
= 17.5m.
Substitute in (1), we get
A = pi(17.5^2 - 14^2)
= pi(17.5 + 14)(17.5-14)
= pi(31.5)(3.5)
= 22 * 31.5 * 3.5/7
= 346.5 sq.m.
Similar questions