Acno when divided by 462 the remainder is 59 if that no divided by 14 the remainder
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0
Let the number = x
when x divided by 462 the remainder is 59
assume quotient is m.
So x = 462m + 59
462 ÷ 14 = 33
So we can write
x = (33×14)m + 59
=> x = 33m × 14 + (56 + 3)
=> x = 33m × 14 + (14×4 + 3)
=> x = 14×(33m + 4) + 3
=> x = 14n + 3
Where n = 33m+4
So when x is divided by 14, remainder will be 3
because x = 14n + 3
when x divided by 462 the remainder is 59
assume quotient is m.
So x = 462m + 59
462 ÷ 14 = 33
So we can write
x = (33×14)m + 59
=> x = 33m × 14 + (56 + 3)
=> x = 33m × 14 + (14×4 + 3)
=> x = 14×(33m + 4) + 3
=> x = 14n + 3
Where n = 33m+4
So when x is divided by 14, remainder will be 3
because x = 14n + 3
Answered by
7
Let the number = x
when x divided by 462 the remainder is 59
assume quotient is m.
So x = 462m + 59
462 ÷ 14 = 33
So we can write
x = (33×14)m + 59
=> x = 33m × 14 + (56 + 3)
=> x = 33m × 14 + (14×4 + 3)
=> x = 14×(33m + 4) + 3
=> x = 14n + 3
Where n = 33m+4
So when x is divided by 14, remainder will be 3
because x = 14n + 3
HOPE SO IT WILL HELP......
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