Acompound poses 8% sulphur by mass the least molecular mass
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Let the least molecular mass of the compound be 'M'
For the compound to have least molecular mass, it must contain only 1 sulphur atom in it.
Therefore, 8% of 'M' = 32
(8 x M)/100 = 32
M = 3200/8
M = 400
Thus, the least molecular mass of the compound is 400
For the compound to have least molecular mass, it must contain only 1 sulphur atom in it.
Therefore, 8% of 'M' = 32
(8 x M)/100 = 32
M = 3200/8
M = 400
Thus, the least molecular mass of the compound is 400
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