Question

Aconductivity cell has two electrodes
20 mm apart & of cross section area 1.8 cm
Find the cell constant.​

Answer 1

Answer:

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Explanation:

cell constant = l/A

                      = 2 cm / 1.8 cm²

                       = 1.11 cm⁻¹

Answer 2

Given :

Distance between the electrodes (L) = 20 mm

Cross-sectional area (A) = 1.8 cm²

To Find :

Cell constant

Solution :

Cell constant of a cell can be defined as the ratio of the distance between the cell electrodes and the cross-sectional area of the electrodes.

We are required to find the cell constant of a cell which have the distance between the electrodes 20 mm and cross-sectional area 1.8 cm².

Cell constant of the cell = $\frac{Distance (L)}{Area (A)}$

                                           = $\frac{20 * 10^-3}{1.8 * 10^-^4}$

                                           = $\frac{20}{0.18}$

                                           = 111.11 m⁻¹

Therefore, the cell constant is found to be 111.11 m⁻¹.