Question

aCosA - bSinA=c then prove that aSinA + bCosA =+_ underRoot a^2+b^2 - c^2

Answer 1

UR ANSWER IS ATTACHED 

Answer 2

∴ squaring both sides, 

... a² cos² x + b² sin² x - 2ab sin x cos x = c² 

∴ a² ( 1 - sin² x ) + b² ( 1 - cos² x ) - 2ab sin x cos x = c² 

∴ a² - a² sin² x + b² - b² cos² x - 2ab sin x cos x = c² 

∴ a² + b² - c² = a² sin² x + b² cos² x + 2ab sin x cos x 

∴ a² + b² - c² = ( a sin x + b cos x )² 

∴ a sin x + b cos x = ± √( a² + b² - c² ). .................................. Q.E.D....

Please mark it as brainiest answer ................