Chemistry, asked by deveshg4644, 1 month ago

across the amount of rust formed on complete rusting of 25 gm of iron

Answers

Answered by XxOfficialsuhuxX

3

Explanation:

Moles of iron = 25.0⋅g55.85⋅g⋅mol−1 = ?? mol. From the stoichiometry of the reaction, HALF

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