Question

ACT
IX Class
Physics Experiment
Note down your observations in table - 1
TABLE - 1
Observation Distance of candle Distance of paper Bigger / smaller Inverted or
No.
from mirror
from mirror than object
erected
+
(Object distance - u) (image distance - v)
1)
10 cm
2)
20cm
3)
30 cm
40 cm
5)
50 cm
60 cm
70 cm
8)
80 cm
9)
90 cm
ale.
novin
abos
Since we know the focal point and center of curvature, now reclassify above observation as shown
in table - 2.
TABLE - 2
ed) II.
Position of
the image
Bigger/smaller
than object
inverted or
errected
Real or
virtual
ble
d
Position of the
candle (object)
Between mirror & F
On focal point
Between F and C
On centre of curvature
Beyond C​

Answer 1

Answer:

Object Distance(u) = 10 cm. (negative)

Focal length of the lens (f) = 5 cm.

We know, convex mirror always forms the virtual, upright and diminished.Also, Object distance in the convex mirror is always negative where as Image distance and focal length are positive.

Now, Applying the Mirror's Formula,

f

1

=

v

1

+

u

1

=

5

1

=

v

1

+

1

=

5

1

=

10v

(10−v)

10v=50−5v

15v=50

v=

3

10

so the image distance (v) =3.33cm.