actice Problems 4
1. An aeroplane on a runway, starts from rest and picks up a velocity of 180 km/h and takes off.
In doing so, it covers a runway of 1.5 km. Calculate (i) the uniform acceleration acting on the
aeroplane and (ii) the time in which it takes off.
Answers
Given data :-
- An aeroplane on a runway, starts from rest and picks up a velocity of 180 km/hr.
- An aeroplane covers a runway of 1.5 km.
Solution :-
Here,
u = initial velocity, v = final velocity, a = acceleration of the particle, t = time taken by particle, s = displacement of the particle.
{According to given}
→ An Aeroplane's initial velocity ( u ) = 0
{because aeroplane at rest}
→ An Aeroplane's final velocity ( v ) = 180km/hr
→ Displacement of an aeroplane ( s ) = 1.5 km
Here we use kinematical equation to find acceleration acting on the aeroplane.
→ v² = u² + 2as
→ v² - u² = 2as
→ 180 - 0 = 2 × a × 1.5
→ 180 = 3 × a i.e.
→ a = 180/3
→ a = 60 km/hr²
{ Note :-
→ 60 km/hr² = [(60×1000)/(60×60)²] m/s²
→ 60 km/hr² = [(60000)/(3600)²] m/s²
→ 60 km/hr² =[60000/12960000] m/s²
→ 60 km/hr² = [1/216] m/s²
→ 60 km/hr² = 0.0046 m/s² }
Now to find the time in which aeroplane takes off. { we use formula of velocity }
→ Velocity = Displacement/Time
→ Time = Displacement/Velocity
→ Time = 1.5/180
→ Time = 1/120
→ Time = 0.0083 hr
{Note :-
→ 0.0083 hr = [0.0083 × ( 60 × 60 ) ] sec
→ 0.0083 hr = [0.0083 × 3600 ] sec
→ 0.0083 hr = 29.88 sec }
Hence,
( i ) The uniform acceleration acting on the aeroplane is 60 km/hr². and
( ii ) The time in which aeroplane takes off is 0.0083 hr.