Question

Action of cold and dilute nitric acid on copper.
write the balanced equation​

Answer 1

Answer:

The reaction is as follows:

4HNO3+Cu→Cu(NO3)2+2NO2+2H2O

Hence, nitrogen dioxide is formed.

Explanation:

Copper is a reddish-brown metal. Copper is oxidized by nitric acid and forms Cu+2 ions. When copper is reacted with cold, dilute nitric acid it yields copper nitrate, water, and nitric oxide. And again it undergoes a reaction with air, which is nitric acid reacts with oxygen and gives nitrogen dioxide.

The reaction is as follows:4HNO3+Cu→Cu(NO3)2+2NO2+2H2O

Answer 2

Answer:

Explanation:

(i) Copper reacts with cold and dilute nitric acid to form copper nitrate, water and nitric oxide.

    3Cu + 8HNO3 → 3Cu(NO3)2 + 4 H2O + 2NO

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