Science, asked by sheejasurya9, 2 months ago

Action of dilute sulphuric acid on the following substances. (warm if necessary)

(a) a metal

(b) a carbonate

(c) a sulphide

(d) a sulphite

Make observations, identify the gas evolved and make deductions.​

Answers

Answered by xgamingpromax
4

Answer:

a Carbonate ok this is right answer

Answered by Anonymous
27

\huge{ \underline{\boxed{\red{ \color{red}{\textsf {\textbf{An}{\color{blue}{\textbf {\textsf{sw}}{\color{green}{\textbf{\textsf{er}}}{\color{orange}{\textsf{\textbf{~:-}}}}}}}}}}}}}

Aim of the experiment : To identify the unknown substance by the addition of dilute sulphuric acid the given substance may be .

  • A sulphide
  • A carbonate or
  • A metal
  • A sulphite

Apparatus and Chemicals : Test tubes , test tube holder , bunsen burner , given unknown substance

  • a sulphide
  • a carbonate
  • or a metal substance

and dilute sulphuric acid (H2SO4)

Procedure : Take A Pinch of unknown substance in a test tube . To it add a few drops of dilute sulphuric acid . Shake it . Warm it , if necessary in bunsen burner flame and note down the observations according to the observation table.

\colorbox{pink}{Observation Table is in attachment }

✰✫✰✫✰✫✰✫✰✫✰✫

♬♫♪

➠ Stay happy N Blessed

\huge\boxed{\texttt{\fcolorbox{black}{pink}{know more}}}

Sulphuric acid is one of the most important chemical .It is used in large number of industries as well as and Laboratories .The production and consumption of sulphuric acid in a country gives us the index of industrial advancement and economic prosperity of that country hence it is called king of chemicals.

Attachments:
Similar questions