Chemistry, asked by Yasaswiniyeshu2003, 11 months ago

action of HI on diethyl ether in hot condition​

Answers

Answered by ItsShreedhar
2

Answer:

Mechanism: Strong acid (HI) protonates the ether oxygen, which turns it into a better leaving group (Step 1, arrows A and B). Next, the iodide ion attacks the carbon in an SN2 reaction (Step 2, arrows C and D) to give the alcohol and methyl iodide. \

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Answered by preeti4488
3

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