Action of Hydrogen iodide (HI) on propyne:
Chemical equation
Explanation
Answers
Answered by
1
Hey Friend,
Alkyne reacts with halogen acids to form alkenes and thereby, alkanes!
H H H i
| | | |
H -- C -- C ||| C -- H + HI ---> H -- C --C = C -- H
| |
H H
H H i H H i
| | | | | |
H -- C -- C = C -- H + HI ---> H -- C -- C -- C -- H
| | | |
H H H i
Hope it helps!
Alkyne reacts with halogen acids to form alkenes and thereby, alkanes!
H H H i
| | | |
H -- C -- C ||| C -- H + HI ---> H -- C --C = C -- H
| |
H H
H H i H H i
| | | | | |
H -- C -- C = C -- H + HI ---> H -- C -- C -- C -- H
| | | |
H H H i
Hope it helps!
Answered by
0
CH3-C(I)=CH2 this will be in major amount according to Markonikovs rule
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