Chemistry, asked by gupta90090, 11 months ago

actionof alcoholic KOH on bromethane

Answers

Answered by sidhartha2975

0

This is an elimination reaction that produces an alkene. ... If the haloalkane is reacted at high temperature with a strong base, dissolved in alcohol, the hydroxides ion behave as a Lowry-Bronsted base - removing a proton and forming an alkene in an elimination reaction.

Answered by farhinshaikh79015

0

Ethene will form

C2H5Br + KOH-_--------> C2H2

+KBr+HOH.

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