Question

Activation energy of reaction is 800 cal at temperature 200k the percentage of molecules have energy greater than ea is

Answer 1

The formulae to be used is :

K = A e–Ea/RT

Where :

T = Temperature

K = Number of molecules.

Ea = activation energy

R = Gas constant = 8.314 J/K/Mol

Convert 800 cal to joules =
3347200 joules

Substituting in the formula :

e {3347.2/(8.314 × 200))}

e (-2.013)

=0.13358 molecules

Answer 2

Answer:

Explanation:

The formulae to be used is :

K = A e–Ea/RT

Where :

T = Temperature

K = Number of molecules.

Ea = activation energy

R = Gas constant = 8.314 J/K/Mol

Convert 800 cal to joules =

3347200 joules

Substituting in the formula :

e {3347.2/(8.314 × 200))}

e (-2.013)

=0.13358 molecules