Question

active mass of 3.9 gm pure benzene present in 2L vessel is

Answer 1

Explanation:

Active mass of 3.9 gm pure benzene present in 2 litre vessel. ... 120 gm of urea are present in 5 litre solution, the active mass of urea. play · The average concentration of Na^(+) ... mass of urea is. play · 1.7g of NH_3(g) is present in a 2-L flask.

Answer 2

Given:

The mass of benzene, w = 3.9 gm

The volume of the container, V = 2 L

To Find:

The active mass of benzene.

Calculation:

- The active mass of a substance is equal to the no of moles of that substance per litre of the solution.

- No of moles of benzene = 3.9 / 78

⇒ n = 0.05 moles

- The active mass of benzene = n/V

⇒ The active mass of benzene = 0.05/2

⇒ The active mass of benzene = 0.025 mol/L

- So, the active mass of benzene is 0.025 mol/L.