Chemistry, asked by svkreddy2007, 9 months ago

active mass of 6.4 g of SO2 in 10 L vessel is

Answers

Answered by subramanyamguntikove

2

Answer:

0.01

Explanation:

C=n/v

n=6.4÷64=0.1

C=0.1/10

=0.01

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