Question

ACTIVITY 2: plz answer this question ​

Answer 1

Answer:

1. angle ABP=30 degree

angle CBP=45 DEGREE

ANGLE BCP=45 degree

2. AP=1m

   BP= SQRT (3)m

    CP=SQRT (3)m

    BC=SQRT(6)m

AC=1+SQRT(3)m

PERIMETER OF ABC= (2+SQRT(6) +1+SQRT(3))m

perimeter of triangle ABC- perimeter of BPC= (2+SQRT(6) +1+SQRT(3))m-(SQRT(3) +SQRT(3) + SQRT(6)) =3-SQRT (3)

   

Step-by-step explanation:

*In triangleABP, two angles are 90 and 60 , therefore the third angle will be   30 as the sum of the three angles should be 180 degrees.

*so the angle CBP= 75 degree-angle ABP=75-30=45 degree.

*cos 60 degree= AP/AB= 1/2,   We know AB=2m ,hence AP=1m

*BP^2 =AB^2-AP^2

*angle bcp= {180- (angleBPC + angle CBP)} degree

hence, angle bcp= 180- (90+45)=45

this makes BP=PC as the triangle PBC becomes an isoceles  triangle. (two angles are 45)

*so BC^2 =BP^2 +PC^2