Chemistry, asked by kjaspahul, 9 months ago

Activity 3.11 of chapter3 chemistry class10​

Answers

Answered by ananyagn2005
1

Answer:

Brief procedure:

Activity 3.11 asks us to react to various metals with dilute hydrochloric acid and observe the reaction.

Observation:

Metals react with dilute hydrochloric acid and form metal chlorides with the evolution of hydrogen gas.Metal(s) + HCl(aq) ———–> Metal Chloride(aq) + H2(g)

E.g.

Ca(s) + 2HCl(aq) ————-> CaCl2(aq) + H2(g)

Order of reactivity:

Ca>Mg>Al>Zn>Fe>Pb>Cu

Reaction of metals with dilute hydrochloric acid

Reaction of metals with dilute hydrochloric acid

Temperature during the reaction:

Experiment done at room temperature (25˚C).

Calcium: 40˚C

Zinc: 34˚C

Iron: 30˚C

Copper: 25˚C

Inference/conclusion:

Metals react with acids to form their salt. The process is exothermic and hydrogen gas is also produced.

Explanation:

hope it helps dr

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