Question

Activity 3
Find the first degree polynomial p(x) with p(0) = 1 and p(1) = 2
General form of a first degree polynomial is p(x) = ax + b.
Here po
Therefore b
Also p(1)
=2
therefore
a x 1+b =
2
a+b
2.
The first degree polynomial p(x) =
238
​

Answer 1

Answer:

p(x) = x+1

Step-by-step explanation:

p(x)= ax+b

given p(0)=1

if we put 0 in place of x we get

p(0)= a×0+b=1

b=1

now we put x=1 in place of x we get

p(1)= a×1+b=2

we know that the value of b is equal to 1

then put b=1

p(1)= a+1=2

we get a=1

then the general form of p(x) is equal to x+1

p(x) = x+1