Math, asked by thararatheesh45, 2 months ago

Activity 3
The sides of a triangle are in the ratio 3:5:7 and its perimeter is 45 cm. What are the
lengths of the sides?​

Answers

Answered by mamtabrijesh
1

Step-by-step explanation:

Let the 1st side of a ∆ be 3x

2nd side = 5x

3rd side = 7x

Perimeter = 45

A/q

3x + 5x + 7x = 45

=> 15 x = 45

=> x = 45/15

= 3

Hence ,

1st side = 3x = 3×3 = 9 cm

2nd side = 5x = 5×3 = 15 cm

3rd side = 7x = 7×3 = 21 cm

Ans...

Hope it helps you...

Answered by sujuraju2015
1

Answer:

3=3×3=9

5=5×3=15

7=7×3=21

Step-by-step explanation:

(let the 3:5:7 be in X form)

=3x+5x+7x=45

=15x=45

=X=45/15

X=3

3x=3×3=9

5x=5×3=15

7x=7×3=21

hope it helps!

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