Math, asked by harshpohane4, 4 months ago

Activity In figure 7.30, side of square ABCD is 7 cm. With centre D and radius p.
sector D - AXC is drawn. Fill in the following boxes properly and finde
the area of the shaded region.
Solution : Area of a square =
(Formula
7
= 49 cm
Area of sector (D- AXC) =
30*3043 (Formula
А
4
Fig. 7.30
7
360
38.5 cm
A (shaded region) = A
-A
cm
cm
cm​

Answers

Answered by jaydip1118
29

Answer:

Required Solution :–

★ The number of deer = 72 ★

Given:

• Half of a herd of deer are grazing in the field and three-fourths of the remaining are playing.

• The rest 9 are drinking water from the pond.

To calculate:

• The number of deer in the herd.

Calculation:

Let us assume the number of deer in the herd as x.

So, as the question states :

›» Half of a herd of deer are grazing in the field.

\rm \red {\implies Number \: of \: those \: who \: are\: grazing = \dfrac{x}{2} }⟹Numberofthosewhoaregrazing=

2

x

Now,

\implies⟹ Remaining deer = \sf {x -\dfrac{x}{2}}x−

2

x

\implies⟹ Remaining deer = \sf {\dfrac{2x-x}{2}}

2

2x−x

\rm \red {\implies Remaining \: deer = \dfrac{x}{2}}⟹Remainingdeer=

2

x

Also, as the question states :

›» Three-fourths of the remaining are playing.

\implies⟹ Number of those who are playing = \sf {\dfrac{3}{4} \: of \: \dfrac{x}{2} }

4

3

of

2

x

\implies⟹ Number of those who are playing = \sf {\dfrac{3}{4} \times \dfrac{x}{2} }

4

3

×

2

x

\implies⟹ Number of those who are playing = \sf {\dfrac{3 \times x}{4 \times 2} }

4×2

3×x

\rm \red {\implies Number \: of \: those \: who \: are\: playing = \dfrac{3x}{8} }⟹Numberofthosewhoareplaying=

8

3x

And the other 9 deer are drinking, thus

\sf { Total \: number \: of \: deer = \dfrac{x}{2} + \dfrac{3x}{8} + 9 }Totalnumberofdeer=

2

x

+

8

3x

+9

→\sf { x = \dfrac{x}{2} + \dfrac{3x}{8} + 9 }x=

2

x

+

8

3x

+9

→\sf { x = \dfrac{4x+3x+72}{8} }x=

8

4x+3x+72

→\sf { x = \dfrac{7x+72}{8} }x=

8

7x+72

→\sf { x \times 8 = 7x+72 }x×8=7x+72

→\sf { 8x = 7x+72 }8x=7x+72

→\sf { 8x - 7x = 72 }8x−7x=72

→\sf { x = 72 }x=72

\rm \green{ \longrightarrow Total \: number \: of \: deer = 72 }⟶Totalnumberofdeer=72

Therefore, the number of deer in the herd is 72 .

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