Question

Activity of a radioactive element decreased to one third of original activity i 0 in 9 years. After further 9 years. Its activity will be

Answer 1

Answer:

Solution:

Activity R+R0e−λt R03=R0e−9λ⇒e−9λ=13 ?. (i) After further 9yrR=Re−λt=R03e−9λ ... (ii) From Eqs. (i) and (ii), R=R09

Answer 2

Answer:

Ggle

Explanation:

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