Math, asked by 4trinasen, 7 months ago

actorise b^3-3b^2+2b-6-ab+3a

Answers

Answered by dilliprasaddhakal528

1

b^3-3b^2+2b-6-ab+3a

= b^2(b-3)+2(b-3)-a(b-3)

=(b-3)(b^2+2-a)

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