actorise:
x y xy 2 2 18 32 48 .
Answers
Answered by
2
X = 6 , Y = 5 .......
Answered by
6
We have:
y2−xy(1−x)−x3=y2−xy+x2y−x3 =(y2−xy)+(x2y−x3) =y(y−x)+x2(y−x) =(y−x)(y+x2)y2-xy1-x-x3=y2-xy+x2y-x3 =y2-xy+x2y-x3 =yy-x+x2y-x =y-xy+x2
∴ y2−xy(1−x)−x3=(y−x)(y+x2)
y2−xy(1−x)−x3=y2−xy+x2y−x3 =(y2−xy)+(x2y−x3) =y(y−x)+x2(y−x) =(y−x)(y+x2)y2-xy1-x-x3=y2-xy+x2y-x3 =y2-xy+x2y-x3 =yy-x+x2y-x =y-xy+x2
∴ y2−xy(1−x)−x3=(y−x)(y+x2)
Similar questions