Question

actually I'm very upset because no one is answering my questions


plz if you want to do my help then solve question 6,8,9,10

Answer 1

hey mate I attach solution for u one by one :)

Answer 2

Hey user

Here is your answer :-

$a = \frac{2}{3} \: \: \: b = \frac{6}{7} \: \: \: c = \frac{7}{12} \\ \\ to \: prove \: > a \times (b + c) = a \times b + a \times c \\ \\ on \: lhs \\ \\ a \times (b + c) \\ \\ = \frac{2}{3} \times ( \frac{6}{7} + \frac{7}{12} ) \\ \\ = \frac{2}{3} \times ( \frac{72 + 49}{84} ) \\ \\ = \frac{2}{3} \times \frac{121}{84} \\ \\ = \frac{121}{126} \\ \\ on \: rhs \\ \\ a \times b + a \times c \\ \\ = \frac{2}{3} \times \frac{6}{7} + \frac{2}{3} \times \frac{7}{12} \\ \\ = \frac{4}{7} + \frac{7}{18 } \\ \\ = \frac{72 + 49}{126} \\ \\ = \frac{121}{126}$
$\frac{2}{11} + \frac{3}{5} - \frac{ -6 }{11} + \frac{4}{5} \\ \\ = \frac{5 \times 2 + 11 \times 3}{11 \times 5} - \frac{ - 6 \times 5 + 11 \times 4}{11 \times 5} \\ \\ = \frac{10 + 33}{55} - \frac{ - 30 + 44}{55} \\ \\ = \frac{43}{55} - \frac{14}{55} \\ \\ = \frac{43 - 14}{55} \\ \\ = \frac{29}{55}$
$let \: the \: other \: number \: be \: x \\ \\ \frac{ - 7}{18} + x = \frac{4}{9} \\ \\ x = \frac{4}{9} + \frac{7}{18} \\ \\ x = \frac{8 + 7}{18} \\ \\ x = \frac{15}{18} \\ \\ so \: the \: other \: number \: is \: \frac{15}{18}$
$let \: the \: other \: number \: be \: x \\ \\ \frac{ - 3}{8} \times x = \frac{ - 15}{18} \\ \\ x = \frac{ - 15}{16} \div \frac{ - 3}{8} \\ \\ x = \frac{ - 15}{16} \times \frac{8}{ - 5} \\ \\ x = 5$
thank you.