Question

actually without solving Find the value of 48^3-30^3-18^3

Answer 1

if a+b+c=0 then a^3+b^3+c^3=3abc

48+(-30)+-(18)=0

48³+30³-18³=3*48*-30*-18

=77760

Answer 2

Answer:

77760

Step-by-step explanation:

Let a=48, b=-30, c=-18

Therefore, we have,

a+b+c=0

we know, according to the identity, if x+y+z=0, x^3+y^3+z^3=3xyz

Therefore,

a^3+b^3+c^3=3abc

or, 48^3-30^3-18^3=77760