Math, asked by aasths7228, 1 year ago

Acute angle of a rhombus whose side is a mean proportional between it's diagonals is ?

Answers

Answered by Shaizakincsem
6

Let the diagonal are x, y in length so

side^2 = xy

Now we know that diagonal bisect at 90 degrees so

side^2 = (x/2)^2 + (y/2)^2

xy = x^2 + y^2/4

x^2 + y^2 - 4xy = 0

x/y + y/x = 4

y/x + 1/y/x = 4

Let y/x = t

t^2 -4t + 1 = 0

t = 4+- underoot 12/2 = 2 +- underoot 3

or y/x = 2 +- underoot 3

Now let the angle is θ

tan θ = y/x = 2- underoot 3  [We have to find acute angle only]

Now tan 15  = tan(45-30) = 1/-1/underoot 3 / 1+ 1/underoot 3 = 2 - underoot 3

So tan θ = tan 15

Hence θ = 15


Answered by pinquancaro
8

Refer to the attached image.

Consider a rhombus ABCD,

Let the length of diagonal AC = 'x' and length of diagonal BD = 'y'.

Let the side of a rhombus be 'a' meters.

It is given that side is a mean proportional between it's diagonals.

Therefore, a^2 = xy

Since diagonals of rhombus are perpendicular bisectors.

Therefore, OA = OC = \frac{x}{2} meter

OB = OD = \frac{y}{2} meter

Consider triangle BOC,

By pythagoras theorem,

BC^2 = OB^2 + OC^2

a^2 = (\frac{x}{2})^2 +(\frac{y}{2})^2

\frac{x^2+y^2}{4} = xy

x^2+y^2 = 4xy

1+(\frac{y}{x})^2= \frac{4y}{x}

Let \frac{y}{x} = t

1+(t)^2= 4t

t^2-4t+1 = 0

t = \frac{4\pm 2\sqrt{3}}{2}

t =2\pm \sqrt{3}

Consider triangle DOC,

Let \angle ODC = \Theta

Consider \tan \Theta = \frac{P}{B}

\tan \Theta = \frac{x}{2} \div \frac{y}{2}

\tan \theta = \frac{y}{x}

Since, \frac{y}{x} = t

\frac{y}{x}=2\pm \sqrt{3}

\frac{x}{y} = \frac{1}{2+\sqrt 3}

Rationalizing, we get

\frac{x}{y} = 2- \sqrt 3

Therefore, \tan \theta = 2 - \sqrt3

Consider,

\tan 15^{\circ}= \tan (45^\circ-30^\circ)

\tan 15^{\circ}= \frac{\tan 45^{\circ}-\tan 30^{\circ}}{1+\tan 45^{\circ}\tan 30^{\circ}}

\tan 15^{\circ}= \frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}

\tan 15^{\circ}= \frac{\sqrt{3}-1}{\sqrt{3}+1}

On rationalizing, we get

\tan 15^\circ = 2+ \sqrt3

Hence, the acute angle of rhombus whose side is a mean proportional between it's diagonals is 15 degrees.

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