Question

acute right 10 digit number having 2 Se Lekar 5 digits which are divisible by 5​

Answer 1

Answer:

Step-by-step explanation:First of all, we need to find the LCM of 2,3,4,5,6,8,9,10.

LCM = 360

Least 5 digit number is 10000.

10000 when divided by 360 leaves a reminder of 280.

360 - 280 = 80

We have to add 80 to get the least 5 digit number divisible by 360.

10000 + 80 = 10080 is divisible by 360

Largest 5 digit number is 99999.

99999 when divided by 360 gives 279 as reminder.

99999 - 279 = 99720, is divisible by 360.

Total number of 5-digit numbers divisible by 360 are

(Largest divisible number - smallest divisible number) / 360 + 1

=(99720 - 10080) / 360 + 1

= 249 + 1

= 250

Happy Learning!!!

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