acylation due to gravity at Earth's surface is g find the effective value of gravity at height of 32 km from sea level
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the ans is 9.81 m/s2 because it reduces due the below the surface but it is negligible so we can take 9.81 m/s2 itself
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Gravity decreases due to increase in height
g' = g(1 - 2h/r)
So new gravity
g' = 9.8 (1- 2(32)/6400)
g'= 9.8 (1- 1/100)
g'=9.8(1-0.01)
g'= 9.8×0.99
g'=9.702 m/s^2
so option b o.99 g m/s^2 is correct
g' = g(1 - 2h/r)
So new gravity
g' = 9.8 (1- 2(32)/6400)
g'= 9.8 (1- 1/100)
g'=9.8(1-0.01)
g'= 9.8×0.99
g'=9.702 m/s^2
so option b o.99 g m/s^2 is correct
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