AD
4. If Fig., If PB || CF and DP || EF, then
DE
8cm
2cm, В
(a)
(b) 3
(a)
E
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3
6 cm
Step-by-step explanation:
If PB||CF and DP||EF
also , In ∆ACF and ∆AEF ,AF is common side
and by the two line are parallel to each other in both the triangle, so these two ∆s are similar
so , AB=2 cm
and AC=8 cm
therefore 8-2 = 6 cm
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