ad=ae and bd = ce prove that triangle abc =triangle acd
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Where's the diagram??
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We have,
AE = AD and CE = BD
=> AE + CE = AD + BD
=> AC = AB ............... (i)
Thus, in △'sAEB and ADC, we have
AE = AD ............ [Given]
∠EAB = ∠DAC .......[Common]
and, AC = AB ......... (i)
So, by SAS criterion of congruence, we obtain
△AEB ≅△ADC
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