AD and BC are equal and perpendicular to a line segment ab show that CD bisects AB.
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Given, AD and BC are two equal perpendiculars to AB.
To prove: CD is the bisector of AB
Proof:
Triangles ΔAOD and ΔBOC are similar by AAS congruency
Since:
(i) ∠A = ∠B (perpendicular angles)
(ii) AD = BC (given)
(iii) ∠AOD = ∠BOC (vertically opposite angles)
∴ ΔAOD ≅ ΔBOC.
So, AO = OB ( by CPCT).
Thus, CD bisects AB (Hence proved).
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