Question

AD and BC are equal perpendiculars to a line segment AB (see Fig. 7.18). Show that triangle ABC=CDA​

Answer 1

Answer:

CD bisects AB

∠BOC = ∠DOC ( ∴ Vertically opposite angles )

DA = BC

∠B = ∠A = 90°

So, by \bf{AAS}AAS congruence condition, ΔBOC ≅ ΔOAD

So,

now CO = OD

so, it bisects AB on point '\bf{O}O '

OA = OB [ by \bf{CPCT}CPCT ]

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\bf{AAS}AAS : Angle-Angle-side

\bf{CPCT}CPCT : Corresponding Parts of Congruent Triangles

Answer 2

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