AD and BC are equal perpendiculars to a line segment AB. Show that CD bisects AB.
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In ΔBOC and ΔAOD,∠BOC = ∠AOD (Vertically opposite angles)∠CBO = ∠DAO (Each 90º)BC = AD (Given)∴ ΔBOC ≅ ΔAOD (AAS congruence rule)∴ BO = AO (By CPCT)⇒ CD bisects AB.
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Question :-
AD and BC are equal perpendiculars to a line segment AB (see figure). Show that CD bisects AB.
Answer :-
In ∆BOC and ∆AOD, we have
∠BOC = ∠AOD
BC = AD [Given]
∠BOC = ∠AOD [Vertically opposite angles]
∴ ∆OBC ≅ ∆OAD [By AAS congruency]
⇒ OB = OA [By C.P.C.T.]
i.e., O is the mid-point of AB.
Thus, CD bisects AB.
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