AD and BC are equal perpendiculars to a line segment AB. Show that CD
bisects AB.
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Step-by-step explanation:
In triangle BOC and AOD
DA = BC ( given)
angle DAO = CBO ( each 90)
angle AOD = BOC ( vertically opposite angles)
therefore , triangle BOC congruent AOD
implies, OC = OD
therefore CD bisects AB
Answered by
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Question :-
AD and BC are equal perpendiculars to a line segment AB (see figure). Show that CD bisects AB.
Answer :-
In ∆BOC and ∆AOD, we have
∠BOC = ∠AOD
BC = AD [Given]
∠BOC = ∠AOD [Vertically opposite angles]
∴ ∆OBC ≅ ∆OAD [By AAS congruency]
⇒ OB = OA [By C.P.C.T.]
i.e., O is the mid-point of AB.
Thus, CD bisects AB.
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