Math, asked by nikunjtawari18, 10 months ago

AD and BE are respectively altitudes of Δ ABC such that AE = BD proove that AD = BE .

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Answered by roja2178

5

Step-by-step explanation:

ΔBCE & ΔBFC,

BA=BA ( Common side)

2. angle BDA= angle AEB = 90°( perpendiculars)

3. AO = BO ( mid pt. theorem)

therefore, by S.A.S, ΔAEB congruent to ΔBEA

By C.P.C.T , BE=CF (proved)

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