AD and BE are respectively altitudes of Δ ABC such that AE = BD proove that AD = BE .
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Step-by-step explanation:
ΔBCE & ΔBFC,
BA=BA ( Common side)
2. angle BDA= angle AEB = 90°( perpendiculars)
3. AO = BO ( mid pt. theorem)
therefore, by S.A.S, ΔAEB congruent to ΔBEA
By C.P.C.T , BE=CF (proved)
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