Question

AD and CE are respectively perpendicular to sides BC and AB of ∆ ABC. If angle ECD=50° find angle BAD.

Answer 1

Name the point of intersection of AD and CE as O

angle ECD= 50 ( given)

By angle sum property in triangle OCD

angle OCD +angle ADC+angle DOC=180

50 + 90 + X = 180

140 +X= 180

X=40

therefore angle DOC= 40

and angle EOA =40 ( vertically oppo angles)

So similarly in triangle AOE

angle E + angle EOA+angle EAO =180

90 + 40 + x= 180

130+x = 180

X= 50

Therefore, angle BAD = 50

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