Question

AD andBD are the tangent to a circle with centre O and BC touches the circle at F if AE =5 cm then perimeter of triangle is​

Answer 1

Answer:

15 cm

Step-by-step explanation:

Given AE=5cm

Perimeter of triangleABC=AB+BC+CA

=AE−BE+AD−CD+BF+CF

As it is seen from the figure

CD=CF,BE=BF (properties of tangent of circles)

=AE+AD (as AE=AD)

=5+5=10cm

Answer 2

Step-by-step explanation:

the perimeterof triangle is 10cm.