AD andBD are the tangent to a circle with centre O and BC touches the circle at F if AE =5 cm then perimeter of triangle is
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Answer:
15 cm
Step-by-step explanation:
Given AE=5cm
Perimeter of triangleABC=AB+BC+CA
=AE−BE+AD−CD+BF+CF
As it is seen from the figure
CD=CF,BE=BF (properties of tangent of circles)
=AE+AD (as AE=AD)
=5+5=10cm
Answered by
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Step-by-step explanation:
the perimeterof triangle is 10cm.
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