AD=BC AND AD PARALLEL TO BC. IS AB=DC? PROVE IT.
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Given
AD=BC and AD∥BC
To prove:
AB=DC
Proof:
In △ABC and △CDA
BC=DA (given)
∠BCA=∠DAC (alternate angles)
AC=AC (common)
∴△ABC≅△CDA [by SAS congruence property]
Hence AB=CD
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