AD=BC,BD=AC. Prove that triangle ABC = triangle BAD
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In triangles ABD and BAC, we have
AD=BC (given);
AB=AB (common);
AC=BD (given).
We can use SSS condition to conclude that △ABD≅△BAC. From this we conclude that
∠ADB=∠BCA and ∠DAB=∠CBA.
Answered by
1
Answer:
In triangles ABD and BAC, we have
AD=BC (given);
AB=AB (common);
AC=BD (given).
We can use SSS condition to conclude that △ABD≅△BAC. From this we conclude that
∠ADB=∠BCA and ∠DAB=∠CBA.
Step-by-step explanation:
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