Question

AD, BE and CF are the three medians of AABC. Prove that
(i) 4(AD + BE + CF) > 3(AB + BC + CA)
(ii) 3(AB + BC + CA) > 2(AD + BE + CF). for class 9​

Answer 1

Answer:

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Step-by-step explanation:

I hope you understood

here in the above answer G is the centroid and centroid will divide the median into 2:1 ratio so please follow that