Question

ad,be cf are three altitudes of triangle abc then find the perimeter of triangle abc >2ad​

Answer 1

Answer:

ΔADC

∠D>∠C

∴ AC > AD

Similarly AB > AD

∴ (AB+AC) > 2AD

(AB+BC) > 2BE

and (AC+BC) > 2CF

∴ 2(AB+BC+CA)>2(AD+BE+CF)

∴ (AB+BC+CA)>(AD+BE+CF)

is the correct answer.