AD bisects CAB if CAD = (8x+6°) and DAB =(X+20°) what is the value of x?
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Answered by
50
both are equal. so 8x+5=x+20
7x=14
x=2
7x=14
x=2
Answered by
94
CAD=(8x+6)
DAB=(x+20)
SO,
8x+6=x+20
8x-x=20-6
7x=14
so,
x=14/7
therefore by dividing 14/7
we get,
x=2
I think it is correct.
DAB=(x+20)
SO,
8x+6=x+20
8x-x=20-6
7x=14
so,
x=14/7
therefore by dividing 14/7
we get,
x=2
I think it is correct.
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