AD is a alternate angle of am isosceles triangle ABC in which AD=AC show that 1) AD bisectes BC 2) AD bisectes angle A
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Step-by-step explanation:
In △ADB and △ADC,
∠ADB=∠ADC[Each 90°]
AB=AC[Given]
AD=AD[Common]
By R.H.S congruency,
△ADB≅△ADC
By C.P.C.T.
BD=CD
∠BAC=∠CAD
Hence proved.
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