Question

AD is a alternate angle of am isosceles triangle ABC in which AD=AC show that 1) AD bisectes BC 2) AD bisectes angle A​

Answer 1

Step-by-step explanation:

In △ADB and △ADC,

∠ADB=∠ADC[Each 90°]

AB=AC[Given]

AD=AD[Common]

By R.H.S congruency,

△ADB≅△ADC

By C.P.C.T.

BD=CD

∠BAC=∠CAD

Hence proved.