Question

Ad is a altitude of an isosceles triangle ABC in which ab equals to AC show that AD is also the median
of the triangle
plZ fast answer this

Answer 1

As we know angles opposite are equal to equal sides

So here AB= AC

THEREFORE <B = <C

now in ABD AND ADC

<B = <C

AB = AC

AD = AD

SO SAS similarity

therefore BD = DC

Answer 2

This is the answer....hope it helps!!