Question

AD is a diameter of a circle and AB is a chord.If AD=34cm, AB=30cm, then find the distance of AB from the centre of the circle.

Answer 1

Answer:

the distance is of 4cm

Step-by-step explanation:

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Answer 2

Answer:

8cm

Step-by-step explanation:

A0= Radius = ½×34= 17

AM= ½ AB = ½ ×30 = 15.

{Perpendicular from centre on a chord bisect the chord)

angle OMA = 90. ( distance is perpendicular)

.°. OA² = OM²+AM². (Pythagoras theorem)

17² = OM² + 15²

289= 225 + OM²

289-225 = OM²

64. = OM²

8². = OM²

8 = OM

OM = 8 cm,.

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