Question

AD is a diameter of a circle and AB is chord. If AD= 34 cm and AB =30 cm, the distance of AB from the centre of the circle is:

(A) 17cm (B) 15cm (C) 4cm (D)8cm

Answer 1

Hey!!!!

Here ∆AOB were O of the centre of the circle is right angle ∆. Thus angle O = 90°

Thus OD = 17cm (d = 2r)

Thus by Pythagoras Theorem,

OB² = AB² - OD²

=> OB² = 30² - 17²

=> OB² = 900 - 289

=> OB = √611

=> OB = 24.7cm

Thus the distance of the chord from the centre is 24.7 cm

Hope this helps

Answer 2

option a is correct answer