Question

Ad is a diameter of a circle if angle bcd is 150 calculate angle bad adb

Answer 1

Step-by-step explanation:

$2 \times \frac{22}{7} \times r$

$2 \times \frac{22}{7} \times 150$

so you now find answer

Answer 2

$\angle BAD=30^{\circ}$

$\angle ADB=60^{\circ}$

Step-by-step explanation:

AD is a diameter of circle

Angle BCD=150 degrees

ABCD is a cyclic quadrilateral

Angle BCD+angle BAD=180 degrees

Reason: Sum of opposite angles of cyclic quadrilateral is equal to 180 degrees.

Substitute the values

$150+\angle BAD=180$

$\angle BAD=180-150=30^{\circ}$

$\angle BAD=30^{\circ}$

Angle subtended at half circle=90 degrees

Therefore, angle ABD=90 degrees

In triangle ABD

$\angle BAD+\angle ABD+\angle ADB=180^{\circ}$

Using triangle angles sum property

Substitute the values

$30+90+\angle ADB=180$

$120+\angle ADB=180$

$\angle ADB=180-120=60^{\circ}$

$\angle ADB=60^{\circ}$

#Learns more:

https://brainly.in/question/7251860:answered by Vedulakrishanchaitan